| ⇦ |
| ⇨ |
In Young’s double slit experiment, when wavelength used is 6000Å and the screen is 40 cm from the slits, the fringes are 0.012 cm wide. What is the distance between the slits?
Options
(a) 0.24 cm
(b) 0.2 cm
(c) 2.4 cm
(d) 0.024 cm
Correct Answer:
0.2 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two waves represented by following equations are travelling in same medium
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- A thermoelectric refrigerator works on
- α- particles, β – particles and γ – rays are all having same energy.
- Stress to strain ratio is equivalent to
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two waves represented by following equations are travelling in same medium
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- A thermoelectric refrigerator works on
- α- particles, β – particles and γ – rays are all having same energy.
- Stress to strain ratio is equivalent to
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply