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In Young’s double slit experiment, the slit seperation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is
Options
(a) 0.50 mm
(b) 1.25 mm
(c) 1.50 mm
(d) 1.75 mm
Correct Answer:
1.25 mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
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