In Young’s double slit experiment the distance between the slits and the screen

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In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width

Options

(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged

Correct Answer:

becomes four times

Explanation:

Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β

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Topics: Ray Optics (94)
Subject: Physics (2479)

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