| ⇦ | 
| ⇨ |
In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width
Options
(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged
Correct Answer:
becomes four times
Explanation:
Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β
Related Questions: - Two bodies A and B having temperature 327° C and 427° C are radiating heat
- The maximum particle velocity in a wave motion is half the wave velocity.
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A siren emitting sound of frequency 800 Hz is going away from a static listener
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies A and B having temperature 327° C and 427° C are radiating heat
- The maximum particle velocity in a wave motion is half the wave velocity.
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A siren emitting sound of frequency 800 Hz is going away from a static listener
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply