In Young’s double slit experiment the distance between the slits and the screen

⇦

⇨

In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width

Options

(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged

Correct Answer:

becomes four times

Explanation:

Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β

Related Questions:

1. A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
2. When we close one slit in the young’s double slit experiment, then
3. Two thin lenses when placed in contact, then the power of combination is +10 D.
4. When an input signal 1 is applied to a NOT gate, then its output is
5. If the value of potential in an A.C circuit is 10 V, the peak value of potential is

Topics: Ray Optics (94)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends