| ⇦ |
| ⇨ |
In which of the following reaction standard entropy change (ΔS⁰) is positive and standard Gibb’s energy change (ΔG⁰) decreases sharply with increasing temperature
Options
(a) C (graphite) + 1/2 O₂(g) → CO(g)
(b) CO(g) + 1/2 O₂(g) → CO₂(g)
(c) Mg(s) + 1/2 O₂(g) → MgO(s)
(d) 1/2 C(graphite) + 1/2 O₂(g) → 1/2 CO₂(g)
Correct Answer:
C (graphite) + 1/2 O₂(g) → CO(g)
Explanation:
C(graphite) + 1/2 O₂(g) → CO(g),
Δn(g) = 1 – 1/2 = 1/2,
As amount of gaseous substance is increasing in product, thus
ΔS is positive for this reaction. And we know that ΔG = ΔH -TΔS. As ΔS is positive, thus increase in temperature will make TΔS more negative and ΔG will decrease.
Related Questions: - MnO₃ in an acidic medium dissociates into
- Polarisation power of a cation increases,when
- Which one of the following statements for the order of a reaction is incorrect
- Which one of the following has ΔS⁰ greater then zero
- Which compound is electron deficient?
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- MnO₃ in an acidic medium dissociates into
- Polarisation power of a cation increases,when
- Which one of the following statements for the order of a reaction is incorrect
- Which one of the following has ΔS⁰ greater then zero
- Which compound is electron deficient?
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply