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In vacuum, to travel distance d, light takes time t and in medium to travel distance 5d, it takes time T. The critical angle of the medium is
Options
(a) sin⁻¹(5T/t)
(b) sin⁻¹(5t/3T)
(c) sin⁻¹(5t/T)
(d) sin⁻¹(3t/5T)
Correct Answer:
sin⁻¹(5t/T)
Explanation:
In vacuum, c = d / t
In medium, v = 5d / T
As refractive index , μ = c / v = (d/t) / (5d/T) = T / 5t
Also, sin C = 1 / μ [If C is critical angle]
Therefore, C = sin⁻¹ [5t / T]
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- A luminous object is seperated from a screen by distance d. A convex lens
- In the phenomenon of electric discharge through gases at low pressure,
- A thermally insulated rigid container contains an ideal gas heated by a filament
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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