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In vacuum, to travel distance d, light takes time t and in medium to travel distance 5d, it takes time T. The critical angle of the medium is
Options
(a) sin⁻¹(5T/t)
(b) sin⁻¹(5t/3T)
(c) sin⁻¹(5t/T)
(d) sin⁻¹(3t/5T)
Correct Answer:
sin⁻¹(5t/T)
Explanation:
In vacuum, c = d / t
In medium, v = 5d / T
As refractive index , μ = c / v = (d/t) / (5d/T) = T / 5t
Also, sin C = 1 / μ [If C is critical angle]
Therefore, C = sin⁻¹ [5t / T]
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the energy of He⁺ electron in first orbit?
- A focal length of a lens is 10 cm. What is power of a lens in dioptre?
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
- A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹
- A body of mass m slides down an incline and reaches the bottom
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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