| ⇦ | 
| ⇨ |
In vacuum, to travel distance d, light takes time t and in medium to travel distance 5d, it takes time T. The critical angle of the medium is
Options
(a) sin⁻¹(5T/t)
(b) sin⁻¹(5t/3T)
(c) sin⁻¹(5t/T)
(d) sin⁻¹(3t/5T)
Correct Answer:
sin⁻¹(5t/T)
Explanation:
In vacuum, c = d / t
In medium, v = 5d / T
As refractive index , μ = c / v = (d/t) / (5d/T) = T / 5t
Also, sin C = 1 / μ [If C is critical angle]
Therefore, C = sin⁻¹ [5t / T]
Related Questions:
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
- The total radiant energy per unit area, normal to the direction of incidence
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- A body of mass 4 kg is accelerated upon by a constant force travels
- The fossil bone has a ¹⁴C:¹²C ratio, which is [1/16] of that in a living animal
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply