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In vacuum, to travel distance d, light takes time t and in medium to travel distance 5d, it takes time T. The critical angle of the medium is
Options
(a) sin⁻¹(5T/t)
(b) sin⁻¹(5t/3T)
(c) sin⁻¹(5t/T)
(d) sin⁻¹(3t/5T)
Correct Answer:
sin⁻¹(5t/T)
Explanation:
In vacuum, c = d / t
In medium, v = 5d / T
As refractive index , μ = c / v = (d/t) / (5d/T) = T / 5t
Also, sin C = 1 / μ [If C is critical angle]
Therefore, C = sin⁻¹ [5t / T]
Related Questions: - A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- Which one of the following is not a unit of young’s modulus?
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- Which one of the following is not a unit of young’s modulus?
- Kirchoff’s I law and II laws of electricity prove respectively the
- The parallel beams of monochromatic light of wavelength 4.5 x10⁻⁷ m passes through
- A ball is dropped from a high rise platform at t = 0 starting from rest
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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