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In the Young’s double slit experiment, the intensity of light at a point on the screen (where the path difference is λ) is K, (λ being the wavelength of light used). The intensity at a point where the path difference is λ/4, will be
Options
(a) K
(b) K/4
(c) K/2
(d) zero
Correct Answer:
K/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
- A dynamo converts
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
- Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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