| ⇦ | 
| ⇨ |
In the Young’s double slit experiment, the intensity of light at a point on the screen (where the path difference is λ) is K, (λ being the wavelength of light used). The intensity at a point where the path difference is λ/4, will be
Options
(a) K
(b) K/4
(c) K/2
(d) zero
Correct Answer:
K/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Magnetic susceptibility of a material is given as
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The product of pressure and volume hve thesame units as the product of
- A nuclear reaction is given as 4 ₁H¹→₂He⁴+₀e¹+energy Mention the type of reaction.
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Magnetic susceptibility of a material is given as
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The product of pressure and volume hve thesame units as the product of
- A nuclear reaction is given as 4 ₁H¹→₂He⁴+₀e¹+energy Mention the type of reaction.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply