| ⇦ | 
| ⇨ |
In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω, then the value of power factor of the circuit is
Options
(a) (4/3)
(b) (3/4)
(c) zero
(d) infinity
Correct Answer:
(4/3)
Explanation:
Power factor cos ɸ = Resistance / Impedance = 4 / 3.
Related Questions: - A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
- A change of 0.04 V takes place between the base and the emitter when an input
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- At what distance from the centre of earth, the value of acceleration due to gravity
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
- A change of 0.04 V takes place between the base and the emitter when an input
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- At what distance from the centre of earth, the value of acceleration due to gravity
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply