In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,

In The Series Resonance The Value Of Impedence Is 3 Physics Question

In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω, then the value of power factor of the circuit is

Options

(a) (4/3)
(b) (3/4)
(c) zero
(d) infinity

Correct Answer:

(4/3)

Explanation:

Power factor cos ɸ = Resistance / Impedance = 4 / 3.

Related Questions:

  1. A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
  2. When two displacements represented by y₁=a sin(?t) are superimposed the motion is
  3. 64 drops of mercury, each charged to a potential of 10 V, are combined
  4. A disc of moment of inertia (9.8/π²) kg m² is rotating at 600 rpm. If the frequency
  5. A p-n-p transistor is used in common emitter mode in an amplifier circuit.

Topics: Alternating Current (96)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*