| ⇦ | 
| ⇨ |
In the reaction : 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate constant k is 3.38 ˣ 10⁻⁵ s⁻¹.After 10 minutes the final pressure of N₂O₅ is
Options
(a) 490 atm
(b) 250 atm
(c) 480 atm
(d) 420 atm
Correct Answer:
490 atm
Explanation:
P₀ = 500 atm. k = 2.303 / t log₁₀ p₀ / p(t), 3.38 ⨯ 10⁻⁵ = 2.303 / 10⨯60 log 500/ p(t) or, 0.00880 = log 500 / p(t) ⇒ 500 / 1.02 = 490 atm.
Related Questions: - At 25⁰ C , the highest osmotic pressure is exhibited by 0.1 M solution of
- CH₃CH₂OH converts into CH₃CHO in the presence of
- When an acid cell is charged, then
- n-Butane and isobutane are
- The bond formed due to sidewise overlapping of π-orbitals is
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At 25⁰ C , the highest osmotic pressure is exhibited by 0.1 M solution of
- CH₃CH₂OH converts into CH₃CHO in the presence of
- When an acid cell is charged, then
- n-Butane and isobutane are
- The bond formed due to sidewise overlapping of π-orbitals is
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply