| ⇦ | 
| ⇨ |
In the reaction : 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate constant k is 3.38 ˣ 10⁻⁵ s⁻¹.After 10 minutes the final pressure of N₂O₅ is
Options
(a) 490 atm
(b) 250 atm
(c) 480 atm
(d) 420 atm
Correct Answer:
490 atm
Explanation:
P₀ = 500 atm. k = 2.303 / t log₁₀ p₀ / p(t), 3.38 ⨯ 10⁻⁵ = 2.303 / 10⨯60 log 500/ p(t) or, 0.00880 = log 500 / p(t) ⇒ 500 / 1.02 = 490 atm.
Related Questions: - If principal quantum number n=4, the total number of orbitals having l=3 is
- Nitrogen is obtained by the thermal decomposition of
- Role of hydrogen peroxide in the above reactions is respectively
- Which one is not equal to zero for an ideal solution
- The oxidation number of P in Mg₂P₂O₇ is
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If principal quantum number n=4, the total number of orbitals having l=3 is
- Nitrogen is obtained by the thermal decomposition of
- Role of hydrogen peroxide in the above reactions is respectively
- Which one is not equal to zero for an ideal solution
- The oxidation number of P in Mg₂P₂O₇ is
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply