| ⇦ | 
| ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - When a p-n junction is reverse biased, then the current through the junction
- Magnetic flux φ (in weber) linked with a closed circuit of resistance 10 Ω varies
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
- Weight of a body of mass m decreases by 1% when it is raised to height h
- Two similar springs P and Q have spring constants Kp and Kq, such that Kp>Kq.
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a p-n junction is reverse biased, then the current through the junction
- Magnetic flux φ (in weber) linked with a closed circuit of resistance 10 Ω varies
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
- Weight of a body of mass m decreases by 1% when it is raised to height h
- Two similar springs P and Q have spring constants Kp and Kq, such that Kp>Kq.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply