| ⇦ |
| ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- The rest energy of an electron is
- In semiconductor at a room temperature
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- The rest energy of an electron is
- In semiconductor at a room temperature
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply