| ⇦ | 
| ⇨ |
In the reaction ₁²H+₁³H+₂⁴He+₀¹n, if the binding energies of ₁²H,₁³H and ₂⁴He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is
Options
(a) a+b+c
(b) a+b-c
(c) c-a-b
(d) c+a-b
Correct Answer:
c-a-b
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- Two identical flutes produce fundamental notes of frequency 300 Hz at 27° C
- The order of radius of the nucleus of an atom is
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- When the angle of incidence is 60° on the surface of a glass slab, it is found
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- Two identical flutes produce fundamental notes of frequency 300 Hz at 27° C
- The order of radius of the nucleus of an atom is
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- When the angle of incidence is 60° on the surface of a glass slab, it is found
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply