| ⇦ |
| ⇨ |
In the electrolysis of water, one faraday of electrical energy would evolve
Options
(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen
Correct Answer:
8 g of oxygen
Explanation:
Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.
Related Questions: - Which one of the following statements concerning lanthanides elements is false
- The bond formed due to sidewise overlapping of π-orbitals is
- The heat of combustion of carbon to CO₂ is -393.5 kJ/mol. The heat released
- How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
- Benzenamine reacts with excess bromine to produce
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statements concerning lanthanides elements is false
- The bond formed due to sidewise overlapping of π-orbitals is
- The heat of combustion of carbon to CO₂ is -393.5 kJ/mol. The heat released
- How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
- Benzenamine reacts with excess bromine to produce
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply