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In the electrolysis of water, one faraday of electrical energy would evolve
Options
(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen
Correct Answer:
8 g of oxygen
Explanation:
Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.
Related Questions: - In the reaction : I₂ + I⁻ → I₃⁻, the Lewis base is
- The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.
- Addition of phosphate fertilizers into water leads to
- Which of the following is expected to form colourless complex
- An aqueous solution of CoCl₂ on addition of excess of concentration HCl
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the reaction : I₂ + I⁻ → I₃⁻, the Lewis base is
- The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.
- Addition of phosphate fertilizers into water leads to
- Which of the following is expected to form colourless complex
- An aqueous solution of CoCl₂ on addition of excess of concentration HCl
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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