| ⇦ | 
| ⇨ |
The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is
Options
(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴
Correct Answer:
2 ˣ 10⁻⁴
Explanation:
K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻
K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.
Related Questions: - 2.76 g of silver carbonate on being strongly heated yield a residue weighing
- Diffusion of solvent through a semi permeable membrane is called
- In which of the following compounds manganese has oxidation number equal
- The oxidation number of P in Mg₂P₂O₇ is
- Which of the following statements is true for the electrochemical Daniel cell
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 2.76 g of silver carbonate on being strongly heated yield a residue weighing
- Diffusion of solvent through a semi permeable membrane is called
- In which of the following compounds manganese has oxidation number equal
- The oxidation number of P in Mg₂P₂O₇ is
- Which of the following statements is true for the electrochemical Daniel cell
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply