| ⇦ | 
| ⇨ |
In Ramsay and Rayleigh’s isolation on noble gases from air, the nitrogen of the air is finally converted into
Options
(a) NaNO₂ only
(b) NO and NO₂
(c) NaNO₃ only
(d) NaNO₂ and NaNO₃
Correct Answer:
NaNO₂ and NaNO₃
Explanation:
Nitrogen is finally converted into NaNO₂ and NaNO₃, in Ramsay and Rayleigh’s method. N₂ + O₂ → 2NO. 2NO + O₂ → 2NO₂. 2NO₂ + 2NaOH → NaNO₂ + NaNO₃ + H₂O.
Related Questions: - In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE
- The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is
- In Kjeldahl’s mathod, the nitrogen present is estimated as
- The range of radius ratio (cationic to anionic) for an octahedral arrangement
- Which of the following can act as both oxidising and reducing agents
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE
- The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is
- In Kjeldahl’s mathod, the nitrogen present is estimated as
- The range of radius ratio (cationic to anionic) for an octahedral arrangement
- Which of the following can act as both oxidising and reducing agents
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply