| ⇦ | 
| ⇨ |
In Ramsay and Rayleigh’s isolation on noble gases from air, the nitrogen of the air is finally converted into
Options
(a) NaNO₂ only
(b) NO and NO₂
(c) NaNO₃ only
(d) NaNO₂ and NaNO₃
Correct Answer:
NaNO₂ and NaNO₃
Explanation:
Nitrogen is finally converted into NaNO₂ and NaNO₃, in Ramsay and Rayleigh’s method. N₂ + O₂ → 2NO. 2NO + O₂ → 2NO₂. 2NO₂ + 2NaOH → NaNO₂ + NaNO₃ + H₂O.
Related Questions: - Solution of sodium metals in liquid ammonia strongly reduces due to the presence
- When 0.1 mol MnO₄²⁻ is oxidised the quantity of electricity required to completely
- Which one among the following contains a phenolic -OH group
- Lanthanide contraction is due to increase in
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Solution of sodium metals in liquid ammonia strongly reduces due to the presence
- When 0.1 mol MnO₄²⁻ is oxidised the quantity of electricity required to completely
- Which one among the following contains a phenolic -OH group
- Lanthanide contraction is due to increase in
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply