| ⇦ |
| ⇨ |
In L-C-R series circuit, an alternating emf e and current i are given by the equations e=100 sin (100t) V.
i=100 sin(100t+π/3)mA .
The average power dissipated in the circuit will be
Options
(a) 100 W
(b) 10 W
(c) 5 W
(d) 2.5 W
Correct Answer:
2.5 W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following phenomenon exhibited the particle nature of light?
- A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
- A student performs an experiment to determine the Young’s modulus of a wire
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following phenomenon exhibited the particle nature of light?
- A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
- A student performs an experiment to determine the Young’s modulus of a wire
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply