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In Cu-ammonia complex, the state of hybridization of Cu²⁺ is
Options
(a) sp³
(b) d³
(c) sp²f
(d) dsp²
Correct Answer:
dsp²
Explanation:
Square planar complex is formed by dsp² hybridisation.
Related Questions: - The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
- Geometrical isomers differ in
- In a zero-order reaction.for every 10°C rise of temperature ,the rate is doubled.
- XeF₂ is isostructural with:
- Choose the correct statements
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
- Geometrical isomers differ in
- In a zero-order reaction.for every 10°C rise of temperature ,the rate is doubled.
- XeF₂ is isostructural with:
- Choose the correct statements
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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