| ⇦ | 
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - The input characteristics of a transistor in CE mode is the graph obtained by plotting
- MA⁻¹T⁻² is the dimensional formula of
- A 5 watt source emits monochromatic light of wavelength 5000Å. When placed
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The input characteristics of a transistor in CE mode is the graph obtained by plotting
- MA⁻¹T⁻² is the dimensional formula of
- A 5 watt source emits monochromatic light of wavelength 5000Å. When placed
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply