| ⇦ |
| ⇨ |
In an isobaric process,when temperature changes from T₁ to T₂, ΔS is equal to
Options
(a) 2.303 Cp log (T₂/T₁)
(b) 2.303 Cp ln(T₂/T₁)
(c) Cp ln (T₁/T₂)
(d) Cv ln (T₂/T₁)
Correct Answer:
2.303 Cp log (T₂/T₁)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If in a container no mass and no heat exchange occurs then it constitutes a
- Diazo-coupling is useful to prepare some
- Which of the following is not correct for ionic crystals
- The reagent with which both acetaldehyde and acetone react easily is
- The gas molecules have r.m.s. velocity of its molecules as 1000 m/s
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If in a container no mass and no heat exchange occurs then it constitutes a
- Diazo-coupling is useful to prepare some
- Which of the following is not correct for ionic crystals
- The reagent with which both acetaldehyde and acetone react easily is
- The gas molecules have r.m.s. velocity of its molecules as 1000 m/s
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply