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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical circular coils A and B are kept on a horizontal tube
- When a spring is extended by 2 cm energy stored is 100 J. When extended further by 2 cm
- A p-n photodiode is made of a material with a band gap of 2.0 eV
- Electrical force is acting between two charges kept in vacuum. A copper plate
- The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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