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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A boat of anchor is rocked by waves whose crests are 100 m apart and velocity
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- A gas is suddenly expanded such that its final volume becomes 3 times
- A man throws balls with the same speed vertically upwards one after the other
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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