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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass m is projected with a velocity v making an angle of 45°
- Two nuclei have their mass numbers into the ratio of 1:3
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
- Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed
- If seperation between screen and source is increased by 2%. What would be the effect
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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