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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charged particle of mass m and charge q moves along a circular path of radius
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- An electron is moving in a circular path under the influence of a transverse magnetic
- Assertion(A) :The change in kinetic energy of a particle is equal to the work done
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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