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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If sink is at a temperature of -39⁰C and source at 0⁰C, then efficiency will be
- An elevator car whose floor to ceiling distance is equal to 2.7m starts
- A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- Which of the following atoms has the lowest ionisation potential?
- If a charge in current of 0.01 A in one coil produces a change in magnetic flux
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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