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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bucket full of water is revolved in a vertical circle of 2m
- A point source emits sound equally in all directions in a non-absorbing medium.
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- In an LCR series A.C circuit, the voltage across each of the components, L, C and R is 50V
- If the alternating current I=I₁ cosωt+I₂ sinωt, then the rms current is given by
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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