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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular disc X of radius R is made from an iron plate of thickness t and another disc
- An amplifier has a voltage gain Av=1000. The voltage gain in dB is
- The self induced e.m.f. in a 0.1 H coil when the current in it is changing
- A beam of light consisting of red, green and blue colours is incident on a right
- In Wheatstone bridge, three resistors P,Q and R are conncected in three arms
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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