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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two metal spheres of radii 0.01m and 0.02m are given a charge of 15mC and 45mC
- The wave function (in SI unit) for a light wave is given as Ψ(x,t)= 10³ sin π
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine
- The charges Q, +q, and +q are placed at the vartices of an equilateral
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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