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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
- Two particles which are initially at rest, move towards each other
- When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
- If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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