| ⇦ | 
| ⇨ |
In a potentiometer experiment two cells of e.m.f. E₁ and E₂ are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of E₂ is reversed, then the balancing length becomes 29 cm. The ratio of e.m.f. of the two cells E₁/E₂ is
Options
(a) (1:1)
(b) (2:1)
(c) (3:1)
(d) (4:1)
Correct Answer:
(3:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
- The maximum and minimum magnitudes of the resultant of two vectors
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
- The maximum and minimum magnitudes of the resultant of two vectors
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply