| ⇦ | 
| ⇨ |
In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to
Options
(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A
Correct Answer:
Q²/2ε₀A
Explanation:
Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A
Related Questions: - The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- A tuning fork gives 4 beats with 50 cm length of a sonometer
- Identify the wrong statement with reference to solar cell
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- A tuning fork gives 4 beats with 50 cm length of a sonometer
- Identify the wrong statement with reference to solar cell
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply