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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin wire of resistance 4 ohm is bent to form a circle. The resistance across
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- The initial rate of increase of current, when a battery of emf 6 V is connected
- Colours appear on a thin soap film and soap bubbles due to the phenomenon of
- A body moves with a uniform acceleration a and zero initial velocity
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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