| ⇦ | 
| ⇨ |
In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A man throws balls with the same speed vertically upwards one after the other
- A point charge is kept at the centre of a metallic insulated spherical shell. Then
- If a steel wire of length l and magnetic moment M is bent into a semicircular arc,
- The identical cells connected in series are needed to heat a wire of length one meter
- Vessel A is filled with hydrogen while vessel B, whose volume is
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A man throws balls with the same speed vertically upwards one after the other
- A point charge is kept at the centre of a metallic insulated spherical shell. Then
- If a steel wire of length l and magnetic moment M is bent into a semicircular arc,
- The identical cells connected in series are needed to heat a wire of length one meter
- Vessel A is filled with hydrogen while vessel B, whose volume is
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply