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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin prism of angle 15⁰ made of glass of refractive index µ₁ = 1.5 is combined
- An inclined plane of length 5.60m making an angle of 45⁰ with the horizontal is placed
- If a body is rolling on the surface, its total energy will be
- The time period of a thin bar magnet in Earth’s magnetic field is T
- If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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