| ⇦ | 
| ⇨ |
Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be
Options
(a) 3
(b) 2
(c) 6
(d) 10
Correct Answer:
6
Explanation:
For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.
Related Questions: - Shearing stress causes change in
- Two Carnot engine A and B are operated in series. The engine A receives
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
- In Young’s double slit experiment with sodium vapour lamp of wavelength
- The potential energy of a long spring when stretched by 2 cm is U.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Shearing stress causes change in
- Two Carnot engine A and B are operated in series. The engine A receives
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
- In Young’s double slit experiment with sodium vapour lamp of wavelength
- The potential energy of a long spring when stretched by 2 cm is U.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply