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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An observer moving away from a stationary source. The observed frequency is half
- An electric dipole of dipole moment p is placed in a uniform external electric field
- Two identical capacitors each of capacitance 5 mF are charged potentials 2 kV and 1 kV
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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