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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- The induced emf in a coil of 10 H inductance in which current varies
- A 10 micro farad capacitor is charged to 500 V and then its plates are joined
- A tyre filled with air (27° C and 2 atm) bursts. The temperature of air is (ˠ=1.5)
- In common base circuit of a transistor, current amplification factor is 0.95.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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