| ⇦ | 
| ⇨ |
In a compound microscope, the focal length of the objective is 2.5 cm and of eye lens is 5 cm. If an object is placed at 3.75 cm before the objective and the image is formed at the least distance of distinct vision, then the distance between two lenses will be
Options
(a) 11.67 cm
(b) 12 cm
(c) 12.75 cm
(d) 13 cm
Correct Answer:
11.67 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle is executing a simple harmonic motion. Its maximum acceleration
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- Magnetic induction produced at the centre of a circular loop carrying current is B.
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
- A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is executing a simple harmonic motion. Its maximum acceleration
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- Magnetic induction produced at the centre of a circular loop carrying current is B.
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
- A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply