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In a circuit, L,C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45⁰. The value of C is
Options
(a) 1/πf(2πfL+R)
(b) 1/πf(2πfL-R)
(c) 1/2πf(2πfL-R)
(d) 1/2πf(2πfL+R)
Correct Answer:
1/2πf(2πfL+R)
Explanation:
The phase difference ɸ between current and voltage is given by
tan ɸ = (Xʟ – Xc) / R
(Xʟ – Xc) / R = tan 45° = 1 ⇒ Xc = X⇒ + R
1 / 2πfC = 2πfL + R
Therefore, C = 1 / 2πf(2πfL + R)
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle with total energy E is moving in a potential energy region U(x)
- Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
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- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
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Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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