⇦ | ⇨ |
In a circuit, L,C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45⁰. The value of C is
Options
(a) 1/πf(2πfL+R)
(b) 1/πf(2πfL-R)
(c) 1/2πf(2πfL-R)
(d) 1/2πf(2πfL+R)
Correct Answer:
1/2πf(2πfL+R)
Explanation:
The phase difference ɸ between current and voltage is given by
tan ɸ = (Xʟ – Xc) / R
(Xʟ – Xc) / R = tan 45° = 1 ⇒ Xc = X⇒ + R
1 / 2πfC = 2πfL + R
Therefore, C = 1 / 2πf(2πfL + R)
Related Questions: - A body is under stress F and has Young’s modulus Y, then the energy
- 10 mA current can pass through a galvanometer of resistance 25 ohm.
- A spherical planet has a mass Mp and diameter Dp. A particle of mass
- A uniform force of (3i+j) Nacts on a particle of mass 2 kg.Hence the particle is displaced
- The motion of a particle along a straight line is described by equation
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body is under stress F and has Young’s modulus Y, then the energy
- 10 mA current can pass through a galvanometer of resistance 25 ohm.
- A spherical planet has a mass Mp and diameter Dp. A particle of mass
- A uniform force of (3i+j) Nacts on a particle of mass 2 kg.Hence the particle is displaced
- The motion of a particle along a straight line is described by equation
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply