| ⇦ | 
| ⇨ |
In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is
Options
(a) 10
(b) 7
(c) 6
(d) 4
Correct Answer:
4
Explanation:
We know, pOH = pK(b) + log{[B⁻]/[HB]},
Since, [B⁻] = [HB] (given).
Therefore pOH = pK(b) ⇒ pOH = 10,
Therefore pH = 14 – 10 = 4.
Related Questions: - In acidic medium, the equivalent weight of KMnO₄ is
- When aniline is treated with chloroform in the presence of alcoholic KOH, the product
- Which of the following is non-permissible?
- The most suitable method of the separation of a 1:1 mixture of ortho-and para
- Which one of the following is not a condensation polymer
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In acidic medium, the equivalent weight of KMnO₄ is
- When aniline is treated with chloroform in the presence of alcoholic KOH, the product
- Which of the following is non-permissible?
- The most suitable method of the separation of a 1:1 mixture of ortho-and para
- Which one of the following is not a condensation polymer
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply