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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A certain mass of gas occupies a volume of 300 c.c. at 27⁰C and 620 mm pressure
- What is formed when nitrobenzene is reduced using zinc and alkali
- Which one of the following has ΔS⁰ greater then zero
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
- Which has least gold number
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain mass of gas occupies a volume of 300 c.c. at 27⁰C and 620 mm pressure
- What is formed when nitrobenzene is reduced using zinc and alkali
- Which one of the following has ΔS⁰ greater then zero
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
- Which has least gold number
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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