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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - NaOH is prepared by the electrolysis of
- If the initial concentration of the reactant is doubled, the time for half
- The unit of second order reaction rate constant is
- A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated.
- Equal volumes of 0.1 M AgNO₃ and 0.2 M NaCl are mixed
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- NaOH is prepared by the electrolysis of
- If the initial concentration of the reactant is doubled, the time for half
- The unit of second order reaction rate constant is
- A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated.
- Equal volumes of 0.1 M AgNO₃ and 0.2 M NaCl are mixed
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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