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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The K(sp) of Ag₂CrO₄, AgCl,AgBr and AgI are respectively. 1.1 ˣ 10⁻¹²,1.8 ˣ 10⁻¹⁰,
- A gas mixture contains 50% He and 50% Methane by volume. What is the percent
- If the value of Cp for nitrogen gas is 7 JK⁻¹mol⁻¹ , then the value
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Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The K(sp) of Ag₂CrO₄, AgCl,AgBr and AgI are respectively. 1.1 ˣ 10⁻¹²,1.8 ˣ 10⁻¹⁰,
- A gas mixture contains 50% He and 50% Methane by volume. What is the percent
- If the value of Cp for nitrogen gas is 7 JK⁻¹mol⁻¹ , then the value
- Nitration of aniline is achieved by
- Shape of Fe(CO)₅ is
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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