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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Maximum number of electrons in a subshell of an atom is determined
- Phenol is heated with pthalic anhydride in the presence of concentrated H₂SO₄.
- For two ionic solids CaO and KI,identify the wrong statements among the following
- A nucleophile must have
- Which of the following gives propyne on hydrolysis
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Maximum number of electrons in a subshell of an atom is determined
- Phenol is heated with pthalic anhydride in the presence of concentrated H₂SO₄.
- For two ionic solids CaO and KI,identify the wrong statements among the following
- A nucleophile must have
- Which of the following gives propyne on hydrolysis
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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