| ⇦ |
| ⇨ |
In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is
Options
(a) 10
(b) 7
(c) 6
(d) 4
Correct Answer:
4
Explanation:
We know, pOH = pK(b) + log{[B⁻]/[HB]},
Since, [B⁻] = [HB] (given).
Therefore pOH = pK(b) ⇒ pOH = 10,
Therefore pH = 14 – 10 = 4.
Related Questions: - Which one of the following liquid pairs will exhibit a positive deviation from
- Propanone and propanal are …. Isomers
- The reaction of an organic compound with ammonia followed by nitration
- Intermolecular hydrogen bond exists in
- Iodoform test is not given by
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following liquid pairs will exhibit a positive deviation from
- Propanone and propanal are …. Isomers
- The reaction of an organic compound with ammonia followed by nitration
- Intermolecular hydrogen bond exists in
- Iodoform test is not given by
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply