| ⇦ | 
| ⇨ |
If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
Related Questions: - Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- A condenser of capacity C is charged to a potential difference of V₁. The plates
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- A condenser of capacity C is charged to a potential difference of V₁. The plates
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply