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If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Rutherford’s α-scattering experiment concludes that
- The nuclei of which one of the following pairs of nuclei are isotones?
- Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
- The horizontal and vertical components of earth’s magnetic field at a place
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Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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