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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric vector vibration of an electromagnetic wave is given by
- The product of pressure and volume hve thesame units as the product of
- Which one of the following statements is not correct in case of a semiconductor?
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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