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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
Related Questions: - A soap bubble is charged to a potential 12V. If its radius is doubled,
- To what temperature should the hydrogen at room temperature (27°C) be heated at constant
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A soap bubble is charged to a potential 12V. If its radius is doubled,
- To what temperature should the hydrogen at room temperature (27°C) be heated at constant
- An observer moving away from a stationary source. The observed frequency is half
- The friction of the air causes a vertical retardation equal to 10%
- A point source emits sound equally in all directions in a non-absorbing medium.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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