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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radiactive substance emits 100 beta particles in the first 2s and 50 beta
- When a current of (2.5±0.5) A flows through a wire, it develops a potential difference
- 4 point charges each +q is placed on the circumference of a circle
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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