| ⇦ | 
| ⇨ |
If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
Related Questions: - A toroid having 200 turns carries a current of 1 A. The average radius of the toroid
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- A thin convex lens of refractive index 1.5 has 20 cm focal length in air. If the lens
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- Identify the paramagnetic substance
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A toroid having 200 turns carries a current of 1 A. The average radius of the toroid
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- A thin convex lens of refractive index 1.5 has 20 cm focal length in air. If the lens
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- Identify the paramagnetic substance
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply