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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charged particle experiences magnetic force in the presence of magnetic field.
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- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
- The wavelength of the first line of Lymasn series for hydrogen atom is equal
- A charge of 40 µC is given to a capacitor having capacitance C=10 µF
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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