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If the value of Cp for nitrogen gas is 7 JK⁻¹mol⁻¹ , then the value of ΔH on heating 28g of nitrogen gas from 0⁰C to 100⁰C at constant pressure will be
Options
(a) 1200 J
(b) 1300 J
(c) 1400 J
(d) 1500 J
Correct Answer:
1400 J
Explanation:
Given, C(p) = 7 J K⁻¹ mol⁻¹. Therefore ΔH = nC(p)ΔT = 28/14 x 7 x (373 – 273), 2 x 7 x 100 = 1400 J.
Related Questions: - Which of the following will not be soluble in sodium hydrogen carbonate
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- Which of the following is non-permissible?
- Which of the following compounds volatilises on heating
- The difference between ΔH and ΔE at 300 K for the reaction
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following will not be soluble in sodium hydrogen carbonate
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- Which of the following is non-permissible?
- Which of the following compounds volatilises on heating
- The difference between ΔH and ΔE at 300 K for the reaction
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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