| ⇦ | 
| ⇨ |
If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
Related Questions: - A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- A particle moves along with x-axis.The position x of particle with respect to time
- A glass slab consists of thin uniform layers of progressively decreasing refractive
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- White light reflected from a soap film (Refractive Index =1.5) has a maxima
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- A particle moves along with x-axis.The position x of particle with respect to time
- A glass slab consists of thin uniform layers of progressively decreasing refractive
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- White light reflected from a soap film (Refractive Index =1.5) has a maxima
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply