| ⇦ | 
| ⇨ |
If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus is nearly
Options
(a) (53/13)¹⁄₃ Rᴀı
(b) 5/3Rᴀı
(c) 3/5Rᴀı
(d) (13/53)¹⁄₃ Rᴀı
Correct Answer:
5/3Rᴀı
Explanation:
Radius of the nucleus is given by,
R = R₀A¹/³ ⇒ R ∝ A¹/³
.·. Rᴀ₁ / Rᴛₑ = [Aᴀ₁ / Aᴛₑ]¹/³ = [27 / 125]¹/³ = 3 / 5
Rᴛₑ = (5 / 3) Rᴀ₁
Related Questions: - A thin rod of length L and mass M is held vertically with one end on the floor
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- what is the electric potential at a distance of 9cm from 3nC?
- Weber/m² is equal to
- The original temperature of a black body is 727⁰C. The temperature at which this black
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin rod of length L and mass M is held vertically with one end on the floor
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- what is the electric potential at a distance of 9cm from 3nC?
- Weber/m² is equal to
- The original temperature of a black body is 727⁰C. The temperature at which this black
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply