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If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- A particle is executing SHM along a straight line. Its velocities at distances
- A source of sound S emitting waves of frequency 100 Hz and an observer
- A disc of mass 100 g is kept floating horizontally in air by firing bullets
- A boy playing on the roof of a 10m high building throws a ball with a speed
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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