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If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is
Options
(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa
Correct Answer:
1.55×10⁵ Pa
Explanation:
Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Figure below shows two paths that may be taken by a gas to go from a state A
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- The momentum of a body is increased by 20%.The percentage increases in kinetic energy
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
- RMS velocity of gas is proportional to
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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