If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm

⇦

⇨

If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm, then ¹²⁵₃₂Te would have its radius approximately as

Options

(a) 9.6 fm
(b) 12.0 fm
(c) 4.8 fm
(d) 6.0 fm

Correct Answer:

6.0 fm

Explanation:

It has been known that a nucleus of mass number A has radius
R = R₀A¹/³, Where R₀ = 1.2 x 10⁻¹⁵ m, and A = mass number
In case of ²⁷₁₃Al, let nuclear radius be R₁ and for ¹²⁵₃₂Te, nuclear radius be R₂
For ²⁷₁₃Al, R₁ = R₀ (27)¹/³ = 3R₀
For ¹²⁵₃₂Te, R₂ = R₀ (125)¹/³ = 5R₀
R₂ / R₁ = 5R₀ / 3R₀ = 5/3 R₁ = 5/3 x 3.6 = 6 fm.

Alternative Explanation:

Nuclear radii R = R₀ (A)¹/³

Where A is the mass number.

.·. Rтₑ / Rᴀ₁ = [Aтₑ / Aᴀ₁]¹/³ = (125 / 27)¹/³ = 5 / 3

(or), Rтₑ = (5 / 3) × Rᴀ₁ = (5 / 3) × 3.6 = 6 fm

Related Questions:

1. When a Daniel cell is connected in the secondary circuit of a potentiometer,
2. The force of repulsion between two electrons at a certain distance is F.
3. Maximum range for a projectile motion is given as R. The maximum height will be
4. A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
5. The refracting angle of a prism is A and refractive index of the material of the prism

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends