If the density of earth is doubled keeping its radius constant then acceleration

⇦

⇨

If the density of earth is doubled keeping its radius constant then acceleration due to gravity will be (g=9.8 m/s²)

Options

(a) 19.6 m/s²
(b) 9.8 m/s²
(c) 4.9 m/s²
(d) 2.45 m/s²

Correct Answer:

19.6 m/s²

Explanation:

Acceleration due to gravity g=GM/R² ——-(1)
The radius is constant, volume also constant.
If volume is constant, density is proportional to mass.(v=m/ρ)
The density is doubled, the mass is also doubled. (M’=2M)
The new acceleration due to gravity g’=GM’/R’²
Put the value M’=2M and R’=R
g’=G(2M)/R²
g’=2GM/R² ——–(2)
Substituting equations (1) and (2), we get
g’=2g
g=9.8 m/s²
g’=2×9.8=19.6 m/s²

Related Questions:

1. Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
2. The height at which the weight of a body becomes 1/16 th, its weight
3. For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
4. A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground
5. If a small sphere is let fall vertically in a large quantity of still liquid of density

Topics: Gravitation (63)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends