IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹

⇦

⇨

IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹ respectively, the ΔH° for the reaction
H₂(g) + Br₂(g) → 2HBr(g) is

Options

(a) -261 kJ
(b) ⁺103 kJ
(c) ⁺261 kJ
(d) -103 kJ

Correct Answer:

-103 kJ

Explanation:

H – H + Br – Br → 2H – Br,
(433) + (192) (2 x 364)
=625 =728
(Energyabsorbed) (Energy released)
Net energy released = 728 – 625 = 103 KJ. i.e. ΔH = -103 KJ.

Related Questions:

1. The hybridisation of B in BF₃ molecules is
2. In the Dumas method of estimation of nitrogen,the nitrogen in the organic compound
3. Vapour density of a gas is 22. What is its molecular weight
4. Picrates formed by
5. If HNO₃ changes into N₂O, the oxidation number is changed by

Topics: Thermodynamics (179)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends