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If rope of lift breaks suddenly, the tension exerted by the surface of the lift (a = Acceleration of lift) is
Options
(a) mg
(b) m(g+a)
(c) zero
(d) m(g-a)
Correct Answer:
zero
Explanation:
If the rope suddenly breaks, acceleration = g
So substituting in formula, tension T=m(g−a)=0
Related Questions: - The period of oscillation of a mass M suspended from a spring of negligible mass is T
- A cricket ball of mass 250 g collides with a bat with velocity 10 m/s
- A car moves from X to Y with a uniform speed v(u) and returns to Y with a uniform speed
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A bullet emerges from a barrel of length 1.2 m with a speed of 640 ms⁻¹.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The period of oscillation of a mass M suspended from a spring of negligible mass is T
- A cricket ball of mass 250 g collides with a bat with velocity 10 m/s
- A car moves from X to Y with a uniform speed v(u) and returns to Y with a uniform speed
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A bullet emerges from a barrel of length 1.2 m with a speed of 640 ms⁻¹.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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