If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is

⇦

⇨

If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is

Options

(a) 4.00 ˣ 10⁻⁶ M³
(b) 4.00 ˣ 10⁻⁷ M³
(c) 5.00 ˣ 10⁻⁶ M³
(d) 5.00 ˣ 10⁻⁷ M³

Correct Answer:

5.00 ˣ 10⁻⁷ M³

Explanation:

We Know, pH + pOH = 14,
Here, 12 + pOH = 14,
pOH = 2,
⇒ [OH⁻] = 10⁻².
Ba(OH)₂ ⇌ Ba²⁺ + 2OH⁻.

2s = [OH⁻] = 10⁻².
s = 10⁻²/2 = 5×10⁻³ M.
K(sp) = [Ba²⁺][OH⁻]² = (5×10⁻³)(10⁻²)²,
K(sp) = 5×10⁻⁷.

Related Questions:

1. The order of filling of electrons inthe orbitals of an atom will be
2. Tollen’s test can be used to distinguish
3. An isomer of ethanol is
4. How many P = O bond present in (HPO₃)₃
5. The ligand N(CH₂CH₂NH₂)₃ is

Topics: Equilibrium (104)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends