| ⇦ | 
| ⇨ |
If ionization potential for hydrogen atom is 13.6eV, then ionization potential for He⁺ will be
Options
(a) 54.4 eV
(b) 6.8 eV
(c) 13.6 eV
(d) 24.5 eV
Correct Answer:
54.4 eV
Explanation:
The ionization energy of any hydrogen like species (having one electron only) is given by the equation I.E = (2π²Z²me⁴)/h². Since the atomic number of H is 1 and that of He is 2, therefore,the I.E. of He⁺ is four times = Z²=(2²) the I.E. of H. So, 13.6 x 4= 54.4 eV
Related Questions: - The ionisation energy of nitrogoen is more than that of oxygen because
- The strongest conjugate base is
- Which of the following possible isomers of butanol has a chiral centre
- Artificial sweetner which is stable under cold conditions only is
- A compound gives a positive test with I₂/NaOH and is extracted from benzene
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionisation energy of nitrogoen is more than that of oxygen because
- The strongest conjugate base is
- Which of the following possible isomers of butanol has a chiral centre
- Artificial sweetner which is stable under cold conditions only is
- A compound gives a positive test with I₂/NaOH and is extracted from benzene
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply