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If ionization potential for hydrogen atom is 13.6eV, then ionization potential for He⁺ will be
Options
(a) 54.4 eV
(b) 6.8 eV
(c) 13.6 eV
(d) 24.5 eV
Correct Answer:
54.4 eV
Explanation:
The ionization energy of any hydrogen like species (having one electron only) is given by the equation I.E = (2π²Z²me⁴)/h². Since the atomic number of H is 1 and that of He is 2, therefore,the I.E. of He⁺ is four times = Z²=(2²) the I.E. of H. So, 13.6 x 4= 54.4 eV
Related Questions: - At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- Give cyclohexanol(I), acetic acid (II), 2,4,6-trinitrophenol(III),and phenol(IV)
- Which of the following is correct relationship
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- Give cyclohexanol(I), acetic acid (II), 2,4,6-trinitrophenol(III),and phenol(IV)
- Which of the following is correct relationship
- The compounds CHCl₃ and HF lead to the formation of a compound of fluorine
- The element that does not form a monoxide is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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